KCET · Physics · Electromagnetic Waves
If \(\mu_{0}\) is permeability of free space and \(\varepsilon_{0}\) is permittivity of free space, the speed of light in vacuum is given by
- A \(\sqrt{\mu_{0} \varepsilon_{0}}\)
- B \(\sqrt{\frac{\mu_{0}}{\varepsilon_{0}}}\)
- C \(\sqrt{\frac{1}{\mu_{0} \varepsilon_{0}}}\)
- D \(\sqrt{\frac{\varepsilon_{0}}{\mu_{0}}}\)
Answer & Solution
Correct Answer
(C) \(\sqrt{\frac{1}{\mu_{0} \varepsilon_{0}}}\)
Step-by-step Solution
Detailed explanation
The speed of light in vacuum is given by \(\sqrt{\frac{1}{\mu_{0} \varepsilon_{0}}}\). where \(\mu_{0}\) is permeability and \(\varepsilon_{0}\) is permittivity of free space.
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