KCET · Physics · Ray Optics

For what distance is ray optics is good approximation when the aperture is \( 4 \mathrm{~mm} \) and the
wavelength of light is \( 400 \mathrm{~nm} \) ?

A \( 24 \mathrm{~m} \)
B \( 40 \mathrm{~m} \)
C \( 18 m \)
D \( 30 \mathrm{~m} \)

Verified Solution

Answer & Solution

Correct Answer

(B) \( 40 \mathrm{~m} \)

Step-by-step Solution

Detailed explanation

Given, aperture, \( a=4 \mathrm{~mm}=4 \times 10^{-3} \mathrm{~m} \); wavelength, \( \lambda=400 \mathrm{~nm}=400 \times 10^{-9} \mathrm{~m} \)
Distance,
\( Z=\frac{a^{2}}{\lambda}=\frac{\left(4 \times 10^{-3}\right)^{2}}{400 \times 10^{-9}}=\frac{4 \times 4 \times 10^{-6}}{400 \times 10^{-9}} \) \( \Rightarrow Z=40 \mathrm{~m} \)
Thus, for \( 40 \mathrm{~m} \) distance ray optics is in good approximation when the aperture is \( 4 \mathrm{~mm} \) and wavelength is \( 40 \mathrm{~nm} \).

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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For what distance is ray optics is good approximation when the aperture is \( 4 \mathrm{~mm} \) and thewavelength of light is \( 400 \mathrm{~nm} \) ?

Step-by-step Solution

For what distance is ray optics is good approximation when the aperture is \( 4 \mathrm{~mm} \) and the
wavelength of light is \( 400 \mathrm{~nm} \) ?