KCET · Physics · Current Electricity
Current flowing through a wire decreases linearly from \(10\) A to zero in \(4\) s as shown in the graph. Find the total charge flowing through the wire in the given time interval.
- A \(40\) C
- B \(20\) C
- C \(10\) C
- D \(80\) C
Answer & Solution
Correct Answer
(B) \(20\) C
Step-by-step Solution
Detailed explanation
The total charge flowing through the wire is given by the area under the current-time (\(I-t\)) graph.
From the given graph, the area is a triangle with base \(t = 4 \text{ s}\) and height \(I = 10 \text{ A}\).
\(Q = \text{Area of triangle} = \dfrac{1}{2} \times \text{base} \times \text{height}\)
\(Q = \dfrac{1}{2} \times 4 \times 10 = 20 \text{ C}\)
Therefore, the total charge flowing through the wire is \(20 \text{ C}\).
Answer: \(20\) C
From the given graph, the area is a triangle with base \(t = 4 \text{ s}\) and height \(I = 10 \text{ A}\).
\(Q = \text{Area of triangle} = \dfrac{1}{2} \times \text{base} \times \text{height}\)
\(Q = \dfrac{1}{2} \times 4 \times 10 = 20 \text{ C}\)
Therefore, the total charge flowing through the wire is \(20 \text{ C}\).
Answer: \(20\) C
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