KCET · Physics · Ray Optics
A ray of light is incident on a plane mirror at an angle of \(60^{\circ}\). The angle of deviation produced by the mirror is
- A \(120^{\circ}\)
- B \(30^{\circ}\)
- C \(60^{\circ}\)
- D \(90^{\circ}\)
Answer & Solution
Correct Answer
(C) \(60^{\circ}\)
Step-by-step Solution
Detailed explanation
Here, angle of incidence, \(i=60^{\circ}\)
\(\therefore\) Angle of deviation
\(\begin{aligned} \delta &=180^{\circ}-(i+r) \\ &=180^{\circ}-2 i \\ &=180^{\circ}-2 \times 60^{\circ}=60^{\circ} \end{aligned} \quad(\) As \(i=r)\)
\(\therefore\) Angle of deviation
\(\begin{aligned} \delta &=180^{\circ}-(i+r) \\ &=180^{\circ}-2 i \\ &=180^{\circ}-2 \times 60^{\circ}=60^{\circ} \end{aligned} \quad(\) As \(i=r)\)
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