A wire of a certain material is stretched slowly by \(10 \%\). Its new resistance and specific resistance becomes respectively

Let initial length of the wire be \(l\). After stretching new length of the wire \(l^{\prime}\) is given as
\(l^{\prime}=l+10 \% \text { of } l=l+\frac{10}{100} l=\frac{11 l}{10}=1 . l\)
i.e. length is increased by 1.1 times
\(\therefore n=1.1\)
We know that, when length of a wire is increased by \(n\) times, then its new resistance is increased by \(n^2\) times i.e. \(R^{\prime}=n^2 R=(1.1)^2 R \quad[\because\) Here, \(n=1.1]\) \(=1.21 \mathrm{R}\)
Specific resistance (resistivity) of a wire does not depends on its dimensions (length, width etc.) because it is a characteristic property of a materia and depends only nature of material of wire. Hence, specific resistance remains same.