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KCET · Maths · Vector Algebra

If \( |\vec{a}|=16,|\vec{b}|=4 \) then, \( \sqrt{|\vec{a} \times \vec{b}|^{2}+|\vec{a} \vec{b}|^{2}} \)

  1. A \( 08 \)
  2. B \( 64 \)
  3. C 4
  4. D \( 16 \)
Verified Solution

Answer & Solution

Correct Answer

(B) \( 64 \)

Step-by-step Solution

Detailed explanation

(B)
\( \sqrt{|\vec{a} \times \vec{b}|^{2}+|\vec{a} \vec{b}|^{2}}=\sqrt{|\vec{a}|^{2}|\vec{b}|^{2}}=|\vec{a}||\vec{b}|=(16)(4)=64 \)