KCET · Physics · Electromagnetic Induction
A rod of length \(2 \mathrm{~m}\) slides with a speed of \(5 \mathrm{~ms}^{-1}\) on a rectangular conducting frame as shown in figure. There exists a uniform magnetic filed of \(0.04 \mathrm{~T}\) perpendicular to the plane of the figure. If the resistance of the rod is \(3 \Omega\). The current through the rod is

- A \(75 \mathrm{~mA}\)
- B \(133 \mathrm{~mA}\)
- C \(0.75 \mathrm{~A}\)
- D \(1.33 \mathrm{~A}\)
Answer & Solution
Correct Answer
(B) \(133 \mathrm{~mA}\)
Step-by-step Solution
Detailed explanation
Given, \(l=2 \mathrm{~m}, v=5 \mathrm{~m} / \mathrm{s}, B=0.04 \mathrm{~T}\) and \(R=3 \Omega\) The current induced in a conducting coil, when moved in a uniform magnetic field is
\(I=\frac{B l v}{R}=\frac{0.04 \times 2 \times 5}{3}=0.133 \mathrm{~A}=133 \mathrm{~mA}\)
\(I=\frac{B l v}{R}=\frac{0.04 \times 2 \times 5}{3}=0.133 \mathrm{~A}=133 \mathrm{~mA}\)
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