KCET · Physics · Ray Optics
A point object \(O\) is placed in front of a glass rod having spherical end of radius of curvature \(30 \mathrm{~cm}\). The image would be formed at
- A \(30 \mathrm{~cm}\) left
- B infinity
- C \(1 \mathrm{~cm}\) to the right
- D \(18 \mathrm{~cm}\) to the left
Answer & Solution
Correct Answer
(A) \(30 \mathrm{~cm}\) left
Step-by-step Solution
Detailed explanation
By using formula, \(\frac{\mu_{2}}{\mathrm{v}}-\frac{\mu_{1}}{\mathrm{u}}=\frac{\mu_{2}-\mu_{1}}{\mathrm{R}}\) \(\Rightarrow \quad \frac{1.5}{\mathrm{v}}-\frac{1}{(-15)}=\frac{(1.5-1)}{+30} \Rightarrow \mathrm{v}=-30 \mathrm{~cm}\)
Negative sign shows that, image is obtained on the same side of object ie, towards left.
Negative sign shows that, image is obtained on the same side of object ie, towards left.
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