KCET · Physics · Electrostatics
A body has a charge of \(-3.2 \mu \mathrm{C}\). The number of excess electrons will be
- A \(5.12 \times 10^{25}\)
- B \(5 \times 10^{12}\)
- C \(2 \times 10^{13}\)
- D \(5.12 \times 10^{13}\)
Answer & Solution
Correct Answer
(C) \(2 \times 10^{13}\)
Step-by-step Solution
Detailed explanation
Charge on body, \(q=-3.2 \mu \mathrm{C}=-3.2 \times 10^{-6} \mathrm{C}\)
\(\therefore\) Number of excess electrons,
\(n=\frac{q}{e}=\frac{-3.2 \times 10^{-6}}{-1.6 \times 10^{-19}}\)
\(=2 \times 10^{13}\)
\(\therefore\) Number of excess electrons,
\(n=\frac{q}{e}=\frac{-3.2 \times 10^{-6}}{-1.6 \times 10^{-19}}\)
\(=2 \times 10^{13}\)
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