KCET · Physics · Wave Optics
A plane wavefront of wavelength \( \lambda \) is incident on a slit of width \( \mathrm{a} \). The angular width of principle
maximum is
- A \( \frac{\lambda}{a} \)
- B \( \frac{(2 \lambda)}{a} \)
- C \( \frac{a}{\lambda} \)
- D \( \frac{a}{(2 \lambda)} \)
Answer & Solution
Correct Answer
(B) \( \frac{(2 \lambda)}{a} \)
Step-by-step Solution
Detailed explanation
Given, wavelength \( =\lambda ; \) width of slit \( =\mathrm{a} . \) Therefore, angular width of central maximum \( 2 \theta=\frac{2 \lambda}{a} \)
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