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KCET · Chemistry · Electrochemistry

\( \mathrm{H}_{2} \mathrm{O}_{2} \) cannot oxidise

  1. A PbS
  2. B \( \mathrm{Na}_{2} \mathrm{SO}_{3} \)
  3. C \( O_{3} \)
  4. D \( K I \)
Verified Solution

Answer & Solution

Correct Answer

(C) \( O_{3} \)

Step-by-step Solution

Detailed explanation

\( \mathrm{H}_{2} \mathrm{O}_{2} \) oxidizes \( \mathrm{Na}_{2} \mathrm{SO}_{3} \) to \( \mathrm{Na}_{2} \mathrm{SO}_{4} \mathrm{KI} \) to \( \mathrm{I}_{2} \) and \( \mathrm{PbS} \) to \( \mathrm{PbSO}_{4} \)
But, does not reduces \( \mathrm{O}_{3} \) to \( \mathrm{O}_{2} \) because both are allotropes so, there are no change in oxidation number occurs
\( \mathrm{H}_{2} \mathrm{O}_{2}+\mathrm{O}_{3} \rightarrow \mathrm{H}_{2} \mathrm{O}+2 \mathrm{O}_{2} \)