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KCET · Maths · Parabola

A stone is thrown vertically upwards from the top of a tower \(64 \mathrm{~m}\) high according to the law \(s=48 t-16 t^{2}\). The greatest height attained by the stone above ground is

  1. A \(36 \mathrm{~m}\)
  2. B \(32 \mathrm{~m}\)
  3. C \(100 \mathrm{~m}\)
  4. D \(64 \mathrm{~m}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(100 \mathrm{~m}\)

Step-by-step Solution

Detailed explanation

Given, \(s=48 t-16 t^{2}\)
\(\Rightarrow \quad \frac{\mathrm{ds}}{\mathrm{dt}}=48-32 \mathrm{t}\)
At the greatest height, \(\mathrm{v}=\frac{\mathrm{ds}}{\mathrm{dt}}=0\)
\(\Rightarrow \quad 48-32 t=0\)
\(\Rightarrow \quad \mathrm{t}=\frac{3}{2}\)
\(\therefore \quad \mathrm{s}=48 \times \frac{3}{2}-16\left(\frac{3}{2}\right)^{2}\)
\(=36 \mathrm{~m}\)
\(\therefore\) Total height \(=64+36=100 \mathrm{~m}\)