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KCET · Maths · Differential Equations

Write the set builder form \( A=\{-1,1\}: \)

  1. A \( A=\{x: x \) is a real number \( \} \)
  2. B \( A=\{x: x \) is an integer \( \} \)
  3. C \( A=\left\{x: x\right. \) is a root of the equation \( \left.x^{2}=1\right\} \)
  4. D \( A=\left\{x: x\right. \) is a root of the equation \( \left.x^{2}+1=0\right\} \)
Verified Solution

Answer & Solution

Correct Answer

(C) \( A=\left\{x: x\right. \) is a root of the equation \( \left.x^{2}=1\right\} \)

Step-by-step Solution

Detailed explanation

Given that, \(A=-\{1,1\}\)
From option \((3), x^{2}=1 \Rightarrow x=\pm 1\)
Therefore, \(A=\left\{x: x\right.\) is a root of the equation \(\left.x^{2}=1\right\}\)