KCET · Maths · Probability
Two dice are thrown simultaneously, the probability of obtaining a total score of \( 5 \) is
- A \( \frac{1}{18} \)
- B \( \frac{1}{12} \)
- C \( \frac{1}{9} \)
- D \( \frac{1}{6} \)
Answer & Solution
Correct Answer
(C) \( \frac{1}{9} \)
Step-by-step Solution
Detailed explanation
Total number of outcomes is \(6 \times 6=36\)
Sum should be 5, that is, \((1,4),(4,1),(2,3),(3,2)\)
Therefore, required probability is
\(P(X)=\frac{4}{36}=\frac{1}{9}\)
Sum should be 5, that is, \((1,4),(4,1),(2,3),(3,2)\)
Therefore, required probability is
\(P(X)=\frac{4}{36}=\frac{1}{9}\)
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