KCET · Maths · Sequences and Series
If \(1+\sin x+\sin ^{2} x+\ldots\) upto \(\infty=4+2 \sqrt{3}\), \(0 < x < \pi\) and \(x \neq \frac{\pi}{2}\), then \(x\) is equal to
- A \(\frac{\pi}{3}, \frac{5 \pi}{6}\)
- B \(\frac{2 \pi}{3}, \frac{\pi}{6}\)
- C \(\frac{\pi}{3}, \frac{2 \pi}{3}\)
- D \(\frac{\pi}{6}, \frac{\pi}{3}\)
Answer & Solution
Correct Answer
(C) \(\frac{\pi}{3}, \frac{2 \pi}{3}\)
Step-by-step Solution
Detailed explanation
Given, \(1+\sin x+\sin ^{2} x+\ldots \infty=4+2 \sqrt{3}\)
\(\Rightarrow \quad \frac{1}{1-\sin x}=4+2 \sqrt{3}\)
\(\Rightarrow \quad 1-\sin x=\frac{1}{4+2 \sqrt{3}} \times \frac{4-2 \sqrt{3}}{4-2 \sqrt{3}}\)
\(\Rightarrow \quad 1-\sin x=\frac{4-2 \sqrt{3}}{4}\)
\(\Rightarrow \quad \quad \sin x=\frac{2 \sqrt{3}}{4}=\frac{\sqrt{3}}{2}\)
\(\Rightarrow \quad x=\frac{\pi}{3}, \frac{2 \pi}{3}\)
\(\Rightarrow \quad \frac{1}{1-\sin x}=4+2 \sqrt{3}\)
\(\Rightarrow \quad 1-\sin x=\frac{1}{4+2 \sqrt{3}} \times \frac{4-2 \sqrt{3}}{4-2 \sqrt{3}}\)
\(\Rightarrow \quad 1-\sin x=\frac{4-2 \sqrt{3}}{4}\)
\(\Rightarrow \quad \quad \sin x=\frac{2 \sqrt{3}}{4}=\frac{\sqrt{3}}{2}\)
\(\Rightarrow \quad x=\frac{\pi}{3}, \frac{2 \pi}{3}\)
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