KCET · Maths · Sequences and Series
The third term of a G.P. is \( 9 \). The product of its first five terms is
- A \( 3^{9} \)
- B \( 3^{12} \)
- C \( 13^{5} \)
- D \( 3^{10} \)
Answer & Solution
Correct Answer
(D) \( 3^{10} \)
Step-by-step Solution
Detailed explanation
(D)
Let \( \frac{a}{r^{2}} \cdot \frac{a}{r} \cdot a \cdot a r \cdot a r^{2} \) are in G.P., Given \( \mathrm{a}=9 \)
\( \therefore \) product \( =9^{5}=3^{10} \)
Let \( \frac{a}{r^{2}} \cdot \frac{a}{r} \cdot a \cdot a r \cdot a r^{2} \) are in G.P., Given \( \mathrm{a}=9 \)
\( \therefore \) product \( =9^{5}=3^{10} \)
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