KCET · Maths · Definite Integration
\(\int\limits_{a-6}^{b-6} f(x + 6)\,dx\) is equal to
- A \(\int\limits_{a}^{b} f(x + 6)\,dx\)
- B \(\int\limits_{a}^{b} f(x - 6)\,dx\)
- C \(\int\limits_{a}^{b} f(x)\,dx\)
- D \(-\int\limits_{a}^{b} f(x)\,dx\)
Answer & Solution
Correct Answer
(C) \(\int\limits_{a}^{b} f(x)\,dx\)
Step-by-step Solution
Detailed explanation
Let \(t = x + 6\).
Differentiating both sides with respect to \(x\), we get \(dt = dx\).
When \(x = a - 6\), \(t = a - 6 + 6 = a\).
When \(x = b - 6\), \(t = b - 6 + 6 = b\).
Substituting these into the integral, we get:
\(\int_{a-6}^{b-6} f(x + 6) \, dx = \int_{a}^{b} f(t) \, dt\)
Using the property of definite integrals \(\int_{a}^{b} f(t) \, dt = \int_{a}^{b} f(x) \, dx\), we get:
\(\int_{a}^{b} f(x) \, dx\)
Answer: \(\int\limits_{a}^{b} f(x)\,dx\)
Differentiating both sides with respect to \(x\), we get \(dt = dx\).
When \(x = a - 6\), \(t = a - 6 + 6 = a\).
When \(x = b - 6\), \(t = b - 6 + 6 = b\).
Substituting these into the integral, we get:
\(\int_{a-6}^{b-6} f(x + 6) \, dx = \int_{a}^{b} f(t) \, dt\)
Using the property of definite integrals \(\int_{a}^{b} f(t) \, dt = \int_{a}^{b} f(x) \, dx\), we get:
\(\int_{a}^{b} f(x) \, dx\)
Answer: \(\int\limits_{a}^{b} f(x)\,dx\)
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