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KCET · Maths · Definite Integration

\(\int\limits_{a-6}^{b-6} f(x + 6)\,dx\) is equal to

  1. A \(\int\limits_{a}^{b} f(x + 6)\,dx\)
  2. B \(\int\limits_{a}^{b} f(x - 6)\,dx\)
  3. C \(\int\limits_{a}^{b} f(x)\,dx\)
  4. D \(-\int\limits_{a}^{b} f(x)\,dx\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\int\limits_{a}^{b} f(x)\,dx\)

Step-by-step Solution

Detailed explanation

Let \(t = x + 6\).

Differentiating both sides with respect to \(x\), we get \(dt = dx\).

When \(x = a - 6\), \(t = a - 6 + 6 = a\).

When \(x = b - 6\), \(t = b - 6 + 6 = b\).

Substituting these into the integral, we get:

\(\int_{a-6}^{b-6} f(x + 6) \, dx = \int_{a}^{b} f(t) \, dt\)

Using the property of definite integrals \(\int_{a}^{b} f(t) \, dt = \int_{a}^{b} f(x) \, dx\), we get:

\(\int_{a}^{b} f(x) \, dx\)

Answer: \(\int\limits_{a}^{b} f(x)\,dx\)