KCET · Maths · Basic of Mathematics
The shaded region in the figure given is the solution of which of the inequations?
- A \(x+y \geq 7,2 x-3 y+6 \leq 0, x \geq 0, y \geq 0\)
- B \(x+y \geq 7,2 x-3 y+6 \geq 0, x \geq 0, y \geq 0\)
- C \(x+y \leq 7,2 x-3 y+6 \leq 0, x \geq 0, y \geq 0\)
- D \(x+y \leq 7,2 x-3 y+6 \geq 0, x \geq 0, y \geq 0\)
Answer & Solution
Correct Answer
(D) \(x+y \leq 7,2 x-3 y+6 \geq 0, x \geq 0, y \geq 0\)
Step-by-step Solution
Detailed explanation
The line joining \(A(7,0)\) and \((0,7)\) is
\(x+y=7\)
And the line jojing \(C(0,2)\) and \(B(3,4)\) is
\(2 x-3 y+6=0\)
\(x, y \geq 0\)
The shaded region is bounded by \(x+y \leq 7\), \(2 x-3 y+6 \geq 0, x \geq 0, y \geq 0\)
Hence, option (d) is correct option.
\(x+y=7\)
And the line jojing \(C(0,2)\) and \(B(3,4)\) is
\(2 x-3 y+6=0\)
\(x, y \geq 0\)
The shaded region is bounded by \(x+y \leq 7\), \(2 x-3 y+6 \geq 0, x \geq 0, y \geq 0\)
Hence, option (d) is correct option.
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