KCET · Maths · Circle
The point \((5,-7)\) lies outside the circle
- A \(x^{2}+y^{2}-8 x=0\)
- B \(x^{2}+y^{2}-5 x+7 y=0\)
- C \(x^{2}+y^{2}-5 x+7 y-1=0\)
- D \(x^{2}+y^{2}-8 x+7 y-2=0\)
Answer & Solution
Correct Answer
(A) \(x^{2}+y^{2}-8 x=0\)
Step-by-step Solution
Detailed explanation
Let \(S=x^{2}+y^{2}-8 x\)
At point \((5,-7)\)
\[
\begin{aligned}
\mathrm{S}=5^{2}+(-7)^{2}-8(5) \\
=& 34>0
\end{aligned}
\]
So, point lies outside the circle.
Hence, option (a) is correct.
At point \((5,-7)\)
\[
\begin{aligned}
\mathrm{S}=5^{2}+(-7)^{2}-8(5) \\
=& 34>0
\end{aligned}
\]
So, point lies outside the circle.
Hence, option (a) is correct.
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