KCET · Chemistry · Some Basic Concepts of Chemistry
What amount of dioxygen (in gram) contains \( 1.8 \times 10^{22} \) molecules ?
- A \( 0.0960 \)
- B \( 0.960 \)
- C \( 9.60 \)
- D \( 96.0 \)
Answer & Solution
Correct Answer
(B) \( 0.960 \)
Step-by-step Solution
Detailed explanation
1 mole of \(O_{2}=6.022 \times 10^{23}\) molecules \(=32 \mathrm{~g}\) of \(O_{2}\)
1 molecule of \(O_{2}=\frac{32}{6.023 \times 10^{23}} g\) of \(O_{2}\)
Therefore, \(1.8 \times 10^{22}\) molecules of \(O_{2}=\frac{32}{6.022 \times 10^{23}} \times 1.8 \times 10^{22} \mathrm{~g}\)
\(=0.960 \mathrm{~g}\) of \(O_{2}\)
1 molecule of \(O_{2}=\frac{32}{6.023 \times 10^{23}} g\) of \(O_{2}\)
Therefore, \(1.8 \times 10^{22}\) molecules of \(O_{2}=\frac{32}{6.022 \times 10^{23}} \times 1.8 \times 10^{22} \mathrm{~g}\)
\(=0.960 \mathrm{~g}\) of \(O_{2}\)
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