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KCET · Chemistry · Some Basic Concepts of Chemistry

What amount of dioxygen (in gram) contains \( 1.8 \times 10^{22} \) molecules ?

  1. A \( 0.0960 \)
  2. B \( 0.960 \)
  3. C \( 9.60 \)
  4. D \( 96.0 \)
Verified Solution

Answer & Solution

Correct Answer

(B) \( 0.960 \)

Step-by-step Solution

Detailed explanation

1 mole of \(O_{2}=6.022 \times 10^{23}\) molecules \(=32 \mathrm{~g}\) of \(O_{2}\)
1 molecule of \(O_{2}=\frac{32}{6.023 \times 10^{23}} g\) of \(O_{2}\)
Therefore, \(1.8 \times 10^{22}\) molecules of \(O_{2}=\frac{32}{6.022 \times 10^{23}} \times 1.8 \times 10^{22} \mathrm{~g}\)
\(=0.960 \mathrm{~g}\) of \(O_{2}\)