KCET · Maths · Circle
The length of the chord joining the points \((4 \cos \theta, 4 \sin \theta)\) and \(\left(4 \cos \left(\theta+60^{\circ}\right)\right.\), \(\left.4 \sin \left(\theta+60^{\circ}\right)\right)\) of the circle \(x^{2}+y^{2}=16\) is
- A 4
- B 8
- C 16
- D 2
Answer & Solution
Correct Answer
(A) 4
Step-by-step Solution
Detailed explanation
Length of the chord
\(
=4 \sqrt{1+1-2 \cos 60^{\circ}}=4
\)
\(
=4 \sqrt{1+1-2 \cos 60^{\circ}}=4
\)
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