KCET · Chemistry · General Organic Chemistry
The number of chain isomers possible for the hydrocarbon with molecular formula \(\text{C}_5\text{H}_{12}\) is
- A \(4\)
- B \(3\)
- C \(2\)
- D \(1\)
Answer & Solution
Correct Answer
(B) \(3\)
Step-by-step Solution
Detailed explanation
The given molecular formula is \(\text{C}_5\text{H}_{12}\), which corresponds to an alkane (pentane).
The possible chain isomers are:
1. n-pentane: \(\text{CH}_3-\text{CH}_2-\text{CH}_2-\text{CH}_2-\text{CH}_3\)
2. isopentane (2-methylbutane): \(\text{CH}_3-\text{CH}(\text{CH}_3)-\text{CH}_2-\text{CH}_3\)
3. neopentane (2,2-dimethylpropane): \(\text{C}(\text{CH}_3)_4\)
Thus, there are \(3\) chain isomers possible for \(\text{C}_5\text{H}_{12}\).
Answer: \(3\)
The possible chain isomers are:
1. n-pentane: \(\text{CH}_3-\text{CH}_2-\text{CH}_2-\text{CH}_2-\text{CH}_3\)
2. isopentane (2-methylbutane): \(\text{CH}_3-\text{CH}(\text{CH}_3)-\text{CH}_2-\text{CH}_3\)
3. neopentane (2,2-dimethylpropane): \(\text{C}(\text{CH}_3)_4\)
Thus, there are \(3\) chain isomers possible for \(\text{C}_5\text{H}_{12}\).
Answer: \(3\)
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