KCET · Maths · Straight Lines
A line passes through \((2,2)\) and is perpendicular to the line \(3 x+y=3\). Its \(y\)-intercept is
- A \(\frac{2}{3}\)
- B \(1\)
- C \(\frac{4}{3}\)
- D \(\frac{1}{3}\)
Answer & Solution
Correct Answer
(C) \(\frac{4}{3}\)
Step-by-step Solution
Detailed explanation
Equation of the line passing through \((2,2)\)
and perpendicular to \(3 x+y=3\)
\((x-2)-3(y-2)=0\)
\(\Rightarrow \quad x-3 y=-4\)
\(\therefore y\) intercept of this line is \(\frac{4}{3}\).
and perpendicular to \(3 x+y=3\)
\((x-2)-3(y-2)=0\)
\(\Rightarrow \quad x-3 y=-4\)
\(\therefore y\) intercept of this line is \(\frac{4}{3}\).
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