KCET · Maths · Probability
In a certain two \(65 \%\) families own cell phones, 15000 families own scooter and 15\% families own both. Taking into consideration that the families own at least one of the two, the total number of families in the town is
- A 20000
- B 30000
- C 40000
- D 50000
Answer & Solution
Correct Answer
(B) 30000
Step-by-step Solution
Detailed explanation
Let the total number of families be \(x\).
Let \(A=\) number of families that own cell phones \(n(A)=\frac{65}{100} \times x\)
Let \(B=\) number of families that own scooter \(n(B)=15000\)
and \((A \cap B)=\) number of families that own cell phones and scooter both
\(n(A \cap B)=\frac{15}{100} \times x\)
Here, \(n(A \cup B)=x\)
\(n(A \cup B)=n(A)+n(B)-n(A \cap B)\)
\(x=\frac{65 x}{100}+15000-\frac{15 x}{100}\)
\(\begin{aligned} \Rightarrow & & 100 x &=65 x+1500000-15 x \\ \Rightarrow & & 100 x-50 x &=1500000 \\ \Rightarrow & & 50 x &=1500000 \\ \Rightarrow & & x &=30000 \end{aligned}\)
Total number of families in the town is 30000 .
Let \(A=\) number of families that own cell phones \(n(A)=\frac{65}{100} \times x\)
Let \(B=\) number of families that own scooter \(n(B)=15000\)
and \((A \cap B)=\) number of families that own cell phones and scooter both
\(n(A \cap B)=\frac{15}{100} \times x\)
Here, \(n(A \cup B)=x\)
\(n(A \cup B)=n(A)+n(B)-n(A \cap B)\)
\(x=\frac{65 x}{100}+15000-\frac{15 x}{100}\)
\(\begin{aligned} \Rightarrow & & 100 x &=65 x+1500000-15 x \\ \Rightarrow & & 100 x-50 x &=1500000 \\ \Rightarrow & & 50 x &=1500000 \\ \Rightarrow & & x &=30000 \end{aligned}\)
Total number of families in the town is 30000 .
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Maths
- If \(f(x)=x e^{x(1-x)}\), then \(f(x)\) isKCET 2024 Easy
- Which of the following is incorrect?
If \(\mathrm{a} \equiv \mathrm{b}(\bmod \mathrm{m})\) and \(\mathrm{x}\) is an integer, thenKCET 2012 Easy - \(\lim _{\mathrm{n} \rightarrow \infty} \mathrm{n} \sin \frac{2 \pi}{3 \mathrm{n}} \cdot \cos \frac{2 \pi}{3 \mathrm{n}}\) isKCET 2010 Easy
- On the set of integers \(Z\), define \(f: Z \rightarrow Z\) as \(f(n)=\left\{\begin{array}{ll}\frac{\mathrm{n}}{2}, & \mathrm{n} \text { is even } \\ 0, & \mathrm{n} \text { is odd }\end{array}\right.\) then \(f\) isKCET 2009 Easy
- \( \int_{0}^{\frac{\pi}{2}} \frac{\sin ^{1000} x d x}{\sin ^{1000} x+\cos ^{1000} x} \) is equal toKCET 2016 Easy
- The derivative of \(\sin x\) with respect to \(\log x\) isKCET 2025 Easy
More PYQs from KCET
- Which of the following hydrides is electron deficient?KCET 2022 Easy
- An organic compound \( \mathrm{X} \) is oxidised by using acidified \( \mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7} \) solution. The product obtained
reacts with phenyl hydrazine but does not answer silver mirror test. The compound \( X \) is,KCET 2016 Medium - The complex formed by a pair of synapsed homologous chromosomes is called,KCET 2023 Easy
- The dimensional formula for impulse isKCET 2007 Easy
- The ratio of the nuclear radii of elements with mass numbers 216 and 125 isKCET 2008 Easy
- \( \int_{-\frac{I}{2}}^{\frac{\pi}{2}} \frac{d x}{e^{\sin x}+1} \) is equal toKCET 2017 Easy