KCET · Maths · Three Dimensional Geometry
\( \int_{-\frac{I}{2}}^{\frac{\pi}{2}} \frac{d x}{e^{\sin x}+1} \) is equal to
- A \( 00 \)
- B \( \pi \)
- C \( -\frac{\pi}{2} \)
- D \( \frac{\pi}{2} \)
Answer & Solution
Correct Answer
(D) \( \frac{\pi}{2} \)
Step-by-step Solution
Detailed explanation
\( I = \int_{-\frac{\pi}{2}}^{\frac{\pi}{2}} \frac{d x}{e^{\sin x}+1} \) Using \( \int_{a}^{b} f(x) dx = \int_{a}^{b} f(a+b-x) dx \), let \( x \to -x \):
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