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KCET · Maths · Differentiation

If \( \mathrm{P}=\left|\begin{array}{ll}x & 1 \\ 1 & x\end{array}\right| \) and \( \mathrm{Q}=\left|\begin{array}{lll}x & 1 & 1 \\ 1 & x & 1 \\ 1 & 1 & x\end{array}\right| \),then \( \frac{d Q}{d x}= \)

  1. A \( 3 P+1 \)
  2. B \( 1-3 P \)
  3. C \( -3 P \)
  4. D \( 3 \mathrm{P} \)
Verified Solution

Answer & Solution

Correct Answer

(D) \( 3 \mathrm{P} \)

Step-by-step Solution

Detailed explanation

Given that
\( P=\left|\begin{array}{ll}x & 1 \\ 1 & x\end{array}\right|, Q=\left|\begin{array}{lll}x & 1 & 1 \\ 1 & x & 1 \\ 1 & 1 & x\end{array}\right| \)
So, \( P=x^{2}-1 \)
And \( Q=x\left(x^{2}-1\right)-(x-1)+(1-x) \)
\( =x^{3}-3 x+2 \)
Now, \( \frac{d Q}{d x}=3 x^{2}-3 \)
\( =3\left(x^{2}-1\right)=3 P \)