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KCET · Maths · Functions

If \(f(x)\) and \(g(x)\) are two functions with \(g(x)=x-\frac{1}{x}\) and \(f \circ g(x)=x^3-\frac{1}{x^3}\), then \(f^{\prime}(x)\) is equals to

  1. A \(3 x^2+\frac{3}{x^4}\)
  2. B \(x^2-\frac{1}{x^2}\)
  3. C \(1-\frac{1}{x^2}\)
  4. D \(3 x^2+3\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(3 x^2+3\)

Step-by-step Solution

Detailed explanation

Here, \(g(x)=x-\frac{1}{x}\)
\(\begin{aligned} & f \circ g(x)=x^3-\frac{1}{x^3}=\left(x-\frac{1}{x}\right)^3+3 x \cdot \frac{1}{x}\left(x-\frac{1}{x}\right) \\ & f \circ g(x)=\left(x-\frac{1}{x}\right)^3+3\left(x-\frac{1}{x}\right) \\ & \therefore f(x)=x^3+3 x \\ & f^{\prime}(x)=3 x^2+3\end{aligned}\)
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