KCET · Maths · Probability
If \( A \) and \( B \) are mutually exclusive events, given that
\( \mathrm{P}(\mathrm{A})=\frac{3}{5}, P(B)=\frac{1}{5} \), then \( \mathrm{P}(\mathrm{A} \) or \( \mathrm{B}) \) is
- A \( 0.8 \)
- B \( 0.6 \)
- C \( 0.4 \)
- D \( 0.2 \)
Answer & Solution
Correct Answer
(A) \( 0.8 \)
Step-by-step Solution
Detailed explanation
Here \( P(A)=\frac{3}{5}, P(B)=\frac{1}{5} \)
For mutually exclusive events \( A \) and \( B \)
\( P(A \) or \( B)=P(A)+P(B) \)
\( \therefore P(A \) or \( B)=\frac{3}{5}+\frac{1}{5}=\frac{4}{5} \)
For mutually exclusive events \( A \) and \( B \)
\( P(A \) or \( B)=P(A)+P(B) \)
\( \therefore P(A \) or \( B)=\frac{3}{5}+\frac{1}{5}=\frac{4}{5} \)
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