KCET · Maths · Functions
If the set \(x\) contains 7 elements and set \(y\) contains 8 elements, then the number of bijections from \(x\) to \(y\) is
- A 0
- B \(8 P_7\)
- C \(7 !\)
- D 8 !
Answer & Solution
Correct Answer
(A) 0
Step-by-step Solution
Detailed explanation
Number of bijections from \(x\) to \(y\) will be zero because only sets with the same cardinality have bijections between them and it is given that number of elements in \(x\) and \(y\) are not same.
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