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KCET · Maths · Matrices

If A and B are invertible matrices of same order, then which of the following is not correct?

  1. A \(A \cdot (\text{adj}A) = (\text{adj}A) \cdot A = A I\)
  2. B \(A \cdot (\text{adj}A) = (\text{adj}A) \cdot A = |A |I\)
  3. C \((AB)^{-1} = B^{-1} A^{-1}\)
  4. D \(|A| \neq 0, |B| \neq 0\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(A \cdot (\text{adj}A) = (\text{adj}A) \cdot A = A I\)

Step-by-step Solution

Detailed explanation

For any square matrix \(A\) of order \(n\), the fundamental property relating the matrix and its adjoint is \(A \cdot (\text{adj}A) = (\text{adj}A) \cdot A = |A| I\), where \(I\) is the identity matrix of order \(n\).

Thus, the statement \(A \cdot (\text{adj}A) = (\text{adj}A) \cdot A = A I\) is incorrect.

Since \(A\) and \(B\) are invertible matrices, their determinants must be non-zero, which means \(|A| \neq 0\) and \(|B| \neq 0\).

The reversal law for the inverse of the product of two invertible matrices states that \((AB)^{-1} = B^{-1} A^{-1}\).

Therefore, the only incorrect statement is the first one.

Answer: \(A \cdot (\text{adj}A) = (\text{adj}A) \cdot A = A I\)