KCET · Maths · Matrices
If A and B are invertible matrices of same order, then which of the following is not correct?
- A \(A \cdot (\text{adj}A) = (\text{adj}A) \cdot A = A I\)
- B \(A \cdot (\text{adj}A) = (\text{adj}A) \cdot A = |A |I\)
- C \((AB)^{-1} = B^{-1} A^{-1}\)
- D \(|A| \neq 0, |B| \neq 0\)
Answer & Solution
Correct Answer
(A) \(A \cdot (\text{adj}A) = (\text{adj}A) \cdot A = A I\)
Step-by-step Solution
Detailed explanation
For any square matrix \(A\) of order \(n\), the fundamental property relating the matrix and its adjoint is \(A \cdot (\text{adj}A) = (\text{adj}A) \cdot A = |A| I\), where \(I\) is the identity matrix of order \(n\).
Thus, the statement \(A \cdot (\text{adj}A) = (\text{adj}A) \cdot A = A I\) is incorrect.
Since \(A\) and \(B\) are invertible matrices, their determinants must be non-zero, which means \(|A| \neq 0\) and \(|B| \neq 0\).
The reversal law for the inverse of the product of two invertible matrices states that \((AB)^{-1} = B^{-1} A^{-1}\).
Therefore, the only incorrect statement is the first one.
Answer: \(A \cdot (\text{adj}A) = (\text{adj}A) \cdot A = A I\)
Thus, the statement \(A \cdot (\text{adj}A) = (\text{adj}A) \cdot A = A I\) is incorrect.
Since \(A\) and \(B\) are invertible matrices, their determinants must be non-zero, which means \(|A| \neq 0\) and \(|B| \neq 0\).
The reversal law for the inverse of the product of two invertible matrices states that \((AB)^{-1} = B^{-1} A^{-1}\).
Therefore, the only incorrect statement is the first one.
Answer: \(A \cdot (\text{adj}A) = (\text{adj}A) \cdot A = A I\)
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