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KCET · Maths · Statistics

The mean of 100 observations is 50 and their standard deviation is 5 . Then, the sum of squares of all observations is

  1. A \(252500\)
  2. B \(250000\)
  3. C \(255000\)
  4. D \(50000\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(252500\)

Step-by-step Solution

Detailed explanation

We know, standard deviation,
\(\begin{aligned} P^2 & =\frac{\Sigma x^2}{n}-(\bar{x})^2 \\ P & =5, \Sigma x=50, n=100\end{aligned}\)
\(\begin{aligned} & \Rightarrow \quad 25=\frac{\Sigma x^2}{100}-(50)^2 \\ & \Rightarrow \quad \Sigma x^2=252500\end{aligned}\)
Thus, sum of squares of all observation in 252500 .