KCET · Chemistry · Solutions
Solubility of \( \mathrm{AgCl} \) is least in
- A \( 0.1 \mathrm{MBaCl}_{2} \)
- B \( 0.1 \mathrm{M} \mathrm{Al} \mathrm{Cl}_{3} \)
- C \( 0.1 \mathrm{M} \mathrm{NaCl} \)
- D Pure water
Answer & Solution
Correct Answer
(A) \( 0.1 \mathrm{MBaCl}_{2} \)
Step-by-step Solution
Detailed explanation
So, for option (A)...in AgCl dissociation the concentration of Cl- ion in reactant side is too much that's why reaction is shifted backward and solubility of AgCl is least.
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