KCET · Chemistry · Coordination Compounds
Which of the following will be able to show geometrical isomerism ?
- A \( \mathrm{MA}_{3} \mathrm{~B} \) - Square planar
- B \( \mathrm{MA}_{2} \mathrm{~B}_{2}- \) Tetrahedral
- C MABCD - Square planar
- D MABCD - Tetrahedral
Answer & Solution
Correct Answer
(C) MABCD - Square planar
Step-by-step Solution
Detailed explanation
Tetrahedral complexes do not show geometrical isomerismbecause due to symmetrical structure, relative positions of
the ligands are same with respect to each other. Square planar complexes of the type \( M A_{3} B \) do not show geometrical
isomerism because the possible spatial arrangements are equivalent. MABCD type square planar complexes shows
three isomers which can be obtained by fixing the position of one ligand and placing any of the remaining three ligands
at the trans-position one by one.



the ligands are same with respect to each other. Square planar complexes of the type \( M A_{3} B \) do not show geometrical
isomerism because the possible spatial arrangements are equivalent. MABCD type square planar complexes shows
three isomers which can be obtained by fixing the position of one ligand and placing any of the remaining three ligands
at the trans-position one by one.



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