KCET · Chemistry · Coordination Compounds
A complex compound in which the oxidation number of a metal is zero is
- A \(\mathrm{K}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]\)
- B \(\mathrm{K}_{3}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]\)
- C \(\left[\mathrm{Ni}(\mathrm{CO})_{4}\right]\)
- D \(\left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{4}\right] \mathrm{Cl}_{2}\)
Answer & Solution
Correct Answer
(C) \(\left[\mathrm{Ni}(\mathrm{CO})_{4}\right]\)
Step-by-step Solution
Detailed explanation
CO is a neutral ligand, so the oxidation state of metal in metal carbonyls is always zero.
\[
\begin{array}{r}
{\left[\mathrm{Ni}(\mathrm{CO})_{4}\right]} \\
\mathrm{x}+(0 \times 4)=0 \\
\mathrm{x}=0
\end{array}
\]
\[
\begin{array}{r}
{\left[\mathrm{Ni}(\mathrm{CO})_{4}\right]} \\
\mathrm{x}+(0 \times 4)=0 \\
\mathrm{x}=0
\end{array}
\]
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