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KCET · Chemistry · Redox Reactions

What is the equivalent weight of \(\mathrm{SnCl}_{2}\) in the following reaction
\(\mathrm{SnCl}_{2}+\mathrm{Cl}_{2} \longrightarrow \mathrm{SnCl}_{4}\) ?

  1. A 95
  2. B 45
  3. C 60
  4. D 30
Verified Solution

Answer & Solution

Correct Answer

(A) 95

Step-by-step Solution

Detailed explanation

\[
\begin{aligned}
\mathrm{SnCl}_{2}+\mathrm{Cl}_{2} & \longrightarrow \mathrm{SnCl}_{4} \\
190 & & \frac{190}{E_{1}} &=\frac{71}{35.5} \\
\Rightarrow & E_{1} &=95
\end{aligned}
\]