KCET · Chemistry · Structure of Atom
The two electrons have the following set of quantum numbers :
\[
\begin{array}{l}
P=3,2,-2,+\frac{1}{2} \\
Q=3,0,0,+\frac{1}{2}
\end{array}
\]
Which of the following statement is true?
- A \( P \) and \( Q \) have same energy
- B \( P \) has greater energy than \( Q \)
- C \( P \) has lesser energy than \( Q \)
- D \( \mathrm{P} \) and \( \mathrm{Q} \) represent same electron
Answer & Solution
Correct Answer
(B) \( P \) has greater energy than \( Q \)
Step-by-step Solution
Detailed explanation
For electron \(P\), the values of quantum numbers are \(n=3, I=2, m l=-2\) and \(s=+1 / 2\). For electron \(Q\) quantum numbers are \(n=3, I=0, m l=0\) and \(s=+1 / 2\). Therefore, from the quantum number values, electron \(P\) belongs to \(3 d-\) orbital and electron \(Q\) to \(3 s\) - orbital. Energy of the orbital is \(s < p < d < f\).
Hence, energy of electron \(P\) is higher than electron \(Q\).
Hence, energy of electron \(P\) is higher than electron \(Q\).
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