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KCET · Chemistry · Solutions

\(3 \mathrm{~g}\) of urea is dissolved in \(45 \mathrm{~g}\) of \(\mathrm{H}_{2} \mathrm{O}\). The relative lowering in vapour pressure is

  1. A \(0.05\)
  2. B \(0.04\)
  3. C \(0.02\)
  4. D \(0.01\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(0.02\)

Step-by-step Solution

Detailed explanation

Relative lowering of vapour pressure
\(\frac{p^{\circ}-p_{s}}{p^{\circ}}=\frac{n_{2}}{n_{1}+n_{2}}\)
where \(p^{\circ}=\) vapour pressure of the pure solvent.
\(p_{s}=\) vapour pressure of the solution
\(n_{2}=\) number of moles of the solute
\(n_{1}=\) number of moles of the solvent
\(n_{2}=\frac{w_{2}}{M_{2}}=\frac{3}{60}=\frac{1}{20}=0.05\)
\(n_{1}=\frac{w_{1}}{M_{1}}=\frac{45}{18}=2.5\)
\(\therefore \quad \frac{p^{\circ}-p_{s}}{p^{\circ}}=\frac{n_{2}}{n_{1}+n_{2}}=\frac{0.05}{2.5+0.05}=0.02\)