KCET · Chemistry · Chemical Kinetics
The synthetically produced radioactive noble gas by the collision of \({ }_{98}^{249} \mathrm{Cf}\) with \({ }_{20}^{48} \mathrm{Ca}\) is
- A radon
- B radium
- C oganesson
- D xenon
Answer & Solution
Correct Answer
(C) oganesson
Step-by-step Solution
Detailed explanation
The reaction of \({ }_{98}^{249} \mathrm{Cf}\) and \({ }_{20}^{40} \mathrm{Ca}\) takes place as follows
\({ }_{98}^{249} \mathrm{Cf}+{ }_{20}^{40} \mathrm{Ca} \longrightarrow{ }_{118}^{294} \mathrm{Og}+3{ }_0^1 n\)
Thus, the radioactive noble gas formed is Oganesson \((Z=118)\)
\({ }_{98}^{249} \mathrm{Cf}+{ }_{20}^{40} \mathrm{Ca} \longrightarrow{ }_{118}^{294} \mathrm{Og}+3{ }_0^1 n\)
Thus, the radioactive noble gas formed is Oganesson \((Z=118)\)
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