KCET · Physics · Magnetic Effects of Current
A particle of charge \(e\) and mass \(m\) moves with a velocity \(v\) in a magnetic field \(B\) applied perpendicular to the motion of the particle. The radius \(r\) of its path in the field is
- A \(\frac{m v}{B e}\)
- B \(\frac{B e}{m v}\)
- C \(\frac{e v}{B m}\)
- D \(\frac{B v}{e m}\)
Answer & Solution
Correct Answer
(A) \(\frac{m v}{B e}\)
Step-by-step Solution
Detailed explanation
Radius of path, \(\quad r-\frac{m v}{q B}\)
Here,
\(q=e\)
So,
\(r=\frac{m v}{e B}\)
Here,
\(q=e\)
So,
\(r=\frac{m v}{e B}\)
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