KCET · Chemistry · Chemical Equilibrium
The standard emf of galvanic cell involving 3 moles of electrons in its redox reaction is \(0.59 \mathrm{~V}\). The equilibrium constant for the reaction of the cell is
- A \(10^{25}\)
- B \(10^{20}\)
- C \(10^{15}\)
- D \(10^{30}\)
Answer & Solution
Correct Answer
(D) \(10^{30}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} \mathrm{E}_{\text {cell }}^{\circ} &=\frac{0.0591}{\mathrm{n}} \log \mathrm{K}_{\mathrm{c}} \\ 0.59 &=\frac{0.0591}{3} \log \mathrm{K}_{\mathrm{c}} \\ \frac{0.59 \times 3}{0.059} &=\log \mathrm{K}_{\mathrm{c}} \\ \therefore \quad \log \mathrm{K}_{\mathrm{c}} &=30 \\ \mathrm{~K}_{\mathrm{c}} &=\text { antilog } 30 \\ &=10^{30} \end{aligned}\)
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