KCET · Chemistry · Structure of Atom
The magnetic moment of a transition metal ion is \(\sqrt{15}\) BM. Therefore, the number of unpaired electrons present in it, is
- A 3
- B 4
- C 1
- D 2
Answer & Solution
Correct Answer
(A) 3
Step-by-step Solution
Detailed explanation
\(\begin{array}{lrl}\mu=\sqrt{n(n+2)} & & \\ \Rightarrow & \sqrt{15} & =\sqrt{n(n+2)} \\ \therefore & n & =3\end{array}\)
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