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KCET · Chemistry · Thermodynamics (C)

The enthalpy of vaporization of benzene is \(+35.3 \mathrm{~kJ} / \mathrm{mol}\) at its boiling point, \(80^{\circ} \mathrm{C}\). The entropy change in the transition of vapour to liquid at its boiling point is

  1. A \(-100\)
  2. B \(+100\)
  3. C \(+342\)
  4. D \(-342\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(-100\)

Step-by-step Solution

Detailed explanation

\[
\begin{aligned}
\Delta H &=+35.3 \mathrm{~kJ} / \mathrm{mol} \\
T &=80^{\circ} \mathrm{C}=80+273=353 \mathrm{~K} \\
\Delta S &=\frac{\Delta H}{T}=\frac{+35.3}{353}=0.1 \mathrm{~kJ} / \mathrm{mol} / \mathrm{K} \\
\Delta S &=0.1 \times 10^{3}=100 \mathrm{~J} / \mathrm{mol} / \mathrm{K}
\end{aligned}
\]
Entropy change in the transition of vapour to liquid is negative, \(\Delta S=-100\).