KCET · Chemistry · Biomolecules
Match List-I with List-II for the following reaction pattern
Glucose \(\xrightarrow{\text { Reagent }}\) Product \(\longrightarrow\) Structural prediction
\begin{array}{|l|l|l|l|}\hline & \text{List - I (Reagents)} & & \text{List-II (Structural prediction)} \\\hline \text{a}. & \text{Acetic anhydride} & \text{(i)} & \text{Glucose has an aldehyde group} \\\hline \text{b.} & \text{Bromine water} & \text{(ii)} & \text{Glucose has a straight chain of six carbon atoms} \\\hline \text{c.} & \text{Hydroiodic acid} & \text{(iii)} & \text{Glucose has five hydroxyl group} \\\hline \text{d.} & \text{Hydrogen cyanide} & \text{(iv)} & \text{Glucose has a carbonyl group} \\\hline\end{array}
Choose the correct answer from the options given below.
- A a-iv, b-iii, c-ii, d-i
- B a-iii, b-i, c-ii, d-iv
- C a-i, b-ii, c-iii, d-iv
- D a-iii, b-ii, c-i, d-iv
Answer & Solution
Correct Answer
(B) a-iii, b-i, c-ii, d-iv
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & a-i i i \\ & b-i \\ & c-i i \\ & d-i v\end{aligned}\)
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