KCET · Chemistry · Thermodynamics (C)
For the reaction \(\mathrm{H}_{2} \mathrm{O}(\mathrm{l}) \rightleftharpoons \mathrm{H}_{2} \mathrm{O}(\mathrm{g})\) at \(373 \mathrm{~K}\) and 1 atm pressure
- A \(\Delta \mathrm{H}=0\)
- B \(\Delta \mathrm{E}=0\)
- C \(\Delta \mathrm{H}=\mathrm{T} \Delta \mathrm{S}\)
- D \(\Delta \mathrm{H}=\Delta \mathrm{E}\)
Answer & Solution
Correct Answer
(C) \(\Delta \mathrm{H}=\mathrm{T} \Delta \mathrm{S}\)
Step-by-step Solution
Detailed explanation
\[
\Delta \mathrm{G}=\Delta \mathrm{H}-\mathrm{T} \cdot \Delta \mathrm{S}
\]
For the reaction,
\[
\begin{array}{cc}
\mathrm{H}_{2} \mathrm{O}(\mathrm{l}) \rightleftharpoons \mathrm{H}_{2} \mathrm{O}(\mathrm{g}) \\
\Delta \mathrm{G}=0 & \text { (at equilibrium) } \\
\Delta \quad \Delta \mathrm{H}=\mathrm{T} \cdot \Delta \mathrm{S}
\end{array}
\]
\Delta \mathrm{G}=\Delta \mathrm{H}-\mathrm{T} \cdot \Delta \mathrm{S}
\]
For the reaction,
\[
\begin{array}{cc}
\mathrm{H}_{2} \mathrm{O}(\mathrm{l}) \rightleftharpoons \mathrm{H}_{2} \mathrm{O}(\mathrm{g}) \\
\Delta \mathrm{G}=0 & \text { (at equilibrium) } \\
\Delta \quad \Delta \mathrm{H}=\mathrm{T} \cdot \Delta \mathrm{S}
\end{array}
\]
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