KCET · Chemistry · Ionic Equilibrium
Conjugate base of \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-}\)is
- A \(\mathrm{HPO}_{4}^{-}\)
- B \(\mathrm{HPO}_{4}^{2-}\)
- C \(\mathrm{H}_{3} \mathrm{PO}_{4}\)
- D \(\mathrm{PO}_{4}^{3-}\)
Answer & Solution
Correct Answer
(B) \(\mathrm{HPO}_{4}^{2-}\)
Step-by-step Solution
Detailed explanation
A conjugate pair of acid and a base differs by a proton only, i.e.,
conjugate acid \(\rightleftharpoons\) conjugate base \(+\mathrm{H}^{+}\)
\(\mathrm{H}_{2} \mathrm{PO}_{4}^{-} \rightleftharpoons \mathrm{HPO}_{4}^{2-}+\mathrm{H}^{+}\)
Thus, \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-}\)can give a proton and hence is an acid while \(\mathrm{HPO}_{4}^{2-}\) can accept the proton and hence is a base.
conjugate acid \(\rightleftharpoons\) conjugate base \(+\mathrm{H}^{+}\)
\(\mathrm{H}_{2} \mathrm{PO}_{4}^{-} \rightleftharpoons \mathrm{HPO}_{4}^{2-}+\mathrm{H}^{+}\)
Thus, \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-}\)can give a proton and hence is an acid while \(\mathrm{HPO}_{4}^{2-}\) can accept the proton and hence is a base.
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