KCET · Chemistry · Solid State
In a face centred cubic arrangement of \( A \) and \( B \) atoms in which 'A' atoms are at the corners of
the unit cell and 'B' atoms are at the face centers. One of the 'A' atom is missing from one
corner in unit cell.the simplest formula of the compound is
- A \( A_{7} B_{24} \)
- B \( A_{7} B_{8} \)
- C \( A B_{3} \)
- D \( A_{7} B_{3} \)
Answer & Solution
Correct Answer
(A) \( A_{7} B_{24} \)
Step-by-step Solution
Detailed explanation
In the given crystal lattice, Atoms of \( A=7 \times \frac{1}{8}=\frac{7}{8} \)
Atom of \( B=6 \times \frac{1}{2}=3 \)
Therefore, the formula is \( \mathrm{A}_{7 / 8} \mathrm{~B}_{3} \) or \( \mathrm{A}_{7} \mathrm{~B}_{24} \)
Atom of \( B=6 \times \frac{1}{2}=3 \)
Therefore, the formula is \( \mathrm{A}_{7 / 8} \mathrm{~B}_{3} \) or \( \mathrm{A}_{7} \mathrm{~B}_{24} \)
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