KCET · Physics · Magnetic Effects of Current
A circular current loop of magnetic moment \( M \) is in an arbitrary orientation in an external uniform magnetic field \( \vec{B} \). The work done to rotate the loop by \( 30^{\circ} \) about an axis perpendicular to its plane is
- A \( \frac{M B}{2} \)
- B MB
- C Zero
- D \( \sqrt{3} \frac{M B}{2} \)
Answer & Solution
Correct Answer
(C) Zero
Step-by-step Solution
Detailed explanation
Even though the coil is rotated, about an axis perpendicular to its plane, the potential energy does not change. Hence, work done is zero.
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