KCET · Chemistry · Ionic Equilibrium
Hydroxyl ion concentration of \(10^{-2} \mathrm{M} \mathrm{HCl}\) is
- A \(1 \times 10^{1} \mathrm{~mol} \mathrm{dm}^{-3}\)
- B \(1 \times 10^{-12} \mathrm{~mol} \mathrm{dm}^{-3}\)
- C \(1 \times 10^{-1} \mathrm{~mol} \mathrm{dm}^{-3}\)
- D \(1 \times 10^{-14} \mathrm{~mol} \mathrm{dm}^{-3}\)
Answer & Solution
Correct Answer
(B) \(1 \times 10^{-12} \mathrm{~mol} \mathrm{dm}^{-3}\)
Step-by-step Solution
Detailed explanation
\(\left[\mathrm{H}^{+}\right]\left[\mathrm{OH}^{-}\right]=10^{-14}\)
\[
\begin{aligned}
{\left[10^{-2}\right]\left[\mathrm{OH}^{-}\right] } &=10^{-14} \\
{\left[\mathrm{OH}^{-}\right] } &=\frac{10^{-14}}{10^{-2}}=10^{-12} \mathrm{~mol} \mathrm{dm}
\end{aligned}
\]
\[
\begin{aligned}
{\left[10^{-2}\right]\left[\mathrm{OH}^{-}\right] } &=10^{-14} \\
{\left[\mathrm{OH}^{-}\right] } &=\frac{10^{-14}}{10^{-2}}=10^{-12} \mathrm{~mol} \mathrm{dm}
\end{aligned}
\]
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