KCET · Physics · Electromagnetic Induction
In a Young's double slit experiment the slit separation is \( 0.5 \mathrm{~m} \) from the slits. For a
monochromatic light of wavelength \( 500 \mathrm{~nm} \), the distance of \( 3^{r d} \) maxima from \( 2^{\text {nd }} \) minima on
the other side is
- A \( 2.75 \mathrm{~mm} \)
- B \( 2.5 \mathrm{~mm} \)
- C \( 22.5 \mathrm{~mm} \)
- D None of above
Answer & Solution
Correct Answer
(D) None of above
Step-by-step Solution
Detailed explanation
Distance between third maxima and second minima on the other side,
\(\begin{aligned} &x=\frac{3 \lambda \mathrm{D}}{\mathrm{d}}+\frac{(2 \times 2-1) \lambda \mathrm{D}}{2 \mathrm{~d}}=\frac{9 \lambda \mathrm{D}}{2 \mathrm{~d}} \\ &\mathrm{x}=\frac{9 \times 500 \times 10^{-9} \times 0.5}{2 \times 0.5 \times 10^{-3}}=2250 \times 10^{-6}=2.25 \mathrm{~mm} \end{aligned}\)
\(\begin{aligned} &x=\frac{3 \lambda \mathrm{D}}{\mathrm{d}}+\frac{(2 \times 2-1) \lambda \mathrm{D}}{2 \mathrm{~d}}=\frac{9 \lambda \mathrm{D}}{2 \mathrm{~d}} \\ &\mathrm{x}=\frac{9 \times 500 \times 10^{-9} \times 0.5}{2 \times 0.5 \times 10^{-3}}=2250 \times 10^{-6}=2.25 \mathrm{~mm} \end{aligned}\)
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