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KCET · Chemistry · d and f Block Elements

How many moles of acidified \(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\) is required to liberate 6 moles of \(\mathrm{I}_{2}\) from an aqueous solution of \(\mathrm{I}^{-}\)?

  1. A 2
  2. B 1
  3. C \(0.25\)
  4. D \(0.5\)
Verified Solution

Answer & Solution

Correct Answer

(A) 2

Step-by-step Solution

Detailed explanation

We know,
\(\mathrm{Cr}_{2} \mathrm{O}_{7}^{-2}+6 \mathrm{I}^{-}+14 \mathrm{H}^{+} \longrightarrow 2 \mathrm{Cr}^{3+}+3 \mathrm{I}_{2}+7 \mathrm{H}_{2} \mathrm{O}\)
Here, 3 moles of \(\mathrm{I}_{2}\) liberation requires one mol of \(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\); for getting 6 moles of \(\mathrm{I}_{2}\), we will require two moles of \(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\).