KCET · Chemistry · d and f Block Elements
How many moles of acidified \(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\) is required to liberate 6 moles of \(\mathrm{I}_{2}\) from an aqueous solution of \(\mathrm{I}^{-}\)?
- A 2
- B 1
- C \(0.25\)
- D \(0.5\)
Answer & Solution
Correct Answer
(A) 2
Step-by-step Solution
Detailed explanation
We know,
\(\mathrm{Cr}_{2} \mathrm{O}_{7}^{-2}+6 \mathrm{I}^{-}+14 \mathrm{H}^{+} \longrightarrow 2 \mathrm{Cr}^{3+}+3 \mathrm{I}_{2}+7 \mathrm{H}_{2} \mathrm{O}\)
Here, 3 moles of \(\mathrm{I}_{2}\) liberation requires one mol of \(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\); for getting 6 moles of \(\mathrm{I}_{2}\), we will require two moles of \(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\).
\(\mathrm{Cr}_{2} \mathrm{O}_{7}^{-2}+6 \mathrm{I}^{-}+14 \mathrm{H}^{+} \longrightarrow 2 \mathrm{Cr}^{3+}+3 \mathrm{I}_{2}+7 \mathrm{H}_{2} \mathrm{O}\)
Here, 3 moles of \(\mathrm{I}_{2}\) liberation requires one mol of \(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\); for getting 6 moles of \(\mathrm{I}_{2}\), we will require two moles of \(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\).
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